4s^2+11s^2-3=0

Solution for 4s^2+11s^2-3=0 equation:

4s^2+11s^2-3=0

We add all the numbers together, and all the variables

15s^2-3=0

a = 15; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·15·(-3)
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{5}}{2*15}=\frac{0-6\sqrt{5}}{30}
=-\frac{6\sqrt{5}}{30}
=-\frac{\sqrt{5}}{5}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{5}}{2*15}=\frac{0+6\sqrt{5}}{30}
=\frac{6\sqrt{5}}{30}
=\frac{\sqrt{5}}{5}
$